diag: H 段(老师 oracle 走 rollout / 前缀消融 / 子目标越过顶点规则 / 分轴与分类别指标);训练:EMA、选模不落在 p_neq 预热、闭环分数选模、24000 步余弦、p_neq 0.5 + p_edge 0.1、子目标头切断抄输入、前缀/dq 增广;仿真:last 记真正提交的候选、碰撞与到达按每题时限、回放门禁读 pass+指纹并走 rollout;数据:动作标签按 1.25·STEP 归一化(act_scale 随 meta/ckpt/ONNX 传递,旧模型 1.0)、收回亏空结转、DAgger 带 qPrev 与起步速度、打包签名变更自动重打;ik-policy.js 同步(actScale、子目标规则、DLS 时清 lastPlan);本机执行清单与 README 更新
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@@ -60,14 +60,15 @@ def measure(d, a, pool):
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# 与池无关的口径:全部有效近邻对(取距离较近的一半,排除远处非线性段)上回归 std ~ a + b·dist,截距 a
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dd = best_d[fin]; jj = best_j[fin]; qf = torch.nonzero(fin).squeeze(1)
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half = dd <= torch.quantile(dd, 0.5)
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Ya, Yb = d.Y[qi][qf[half], :3].float(), d.Y[pi][jj[half], :3].float()
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# 2026-10-19:Y 以 act_scale·STEP 为单位(DATA_VER 2 起 1.25),乘回 act_scale 让判据仍是「STEP 的比例」,与旧数据可比
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Ya, Yb = d.Y[qi][qf[half], :3].float() * d.act_scale, d.Y[pi][jj[half], :3].float() * d.act_scale
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sa = (Ya - Yb).pow(2).mean(-1).mean(-1).sqrt() / math.sqrt(2)
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A = torch.stack([torch.ones_like(dd[half]), dd[half]], 1)
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coef = torch.linalg.lstsq(A.cpu(), sa.cpu()[:, None]).solution.squeeze(1)
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std_norm = max(0.0, coef[0].item())
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thr = torch.quantile(best_d[fin], a.frac)
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m = fin & (best_d <= thr)
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Yq, Yp = d.Y[qi][m, :3].float(), d.Y[pi][best_j[m], :3].float()
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Yq, Yp = d.Y[qi][m, :3].float() * d.act_scale, d.Y[pi][best_j[m], :3].float() * d.act_scale
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rms = (Yq - Yp).pow(2).mean(-1).mean(-1).sqrt() # 每对、6 轴 × 3 步平均
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std = (rms / math.sqrt(2))
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return {'pairs': int(m.sum()), 'pool': P, 'queries': Q, 'nn_dist_threshold': thr.item(),
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